1/5(x)^2=x-4/5

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Solution for 1/5(x)^2=x-4/5 equation: 


x in (-oo:+oo)

(1/5)*x^2 = x-(4/5) // - x-(4/5)

(1/5)*x^2-x+4/5 = 0

1/5*x^2-x+4/5 = 0

DELTA = (-1)^2-(1/5*4/5*4)

DELTA = 9/25

DELTA > 0

x = ((9/25)^(1/2)+1)/(1/5*2) or x = (1-(9/25)^(1/2))/(1/5*2)

x = 4 or x = 1

x in { 1, 4 }

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